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0 votes
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in Binomial theorem by (52.7k points)

If N = (111....1) n times, then

(A)  N is divisible by 71 whenever n is a multiple of 5

(B)  N is divisible by 91 whenever n is a multiple of 6

(C)  N is divisible by 41 whenever n is a multiple of 5

(D)  N is divisible by 71 whenever n is a multiple of 6

1 Answer

+1 vote
by (46.6k points)
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Best answer

Correct option (B), (C)

If n = 5a (where a is an integer),

So, N is divisible by 41 if n = 5a.

If n = 6a (where a is an integer),

So, N is divisible by 91 if n = 6a

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