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in Binomial theorem by (52.7k points)

Let A1, A2, A3, …, Am be the arithmetic means between -2 and 1027 and G1, G2, G3, …, Gn be the geometric means between 1 and 1024. Product of the geometric means is 245 and the sum of arithmetic means is 1025 x 171.

1.  The value of n is

(A)  7

(B)  9 

(C)  11

(D)  None of these

2.  The value of m is

(A)  340

(B)  342

(C)  344

(D)  346

3.  The value of G1 + G2 + G3 + . . . + Gn is

(A)  1022

(B)  2044 

(C)  512

(D)  None of these

1 Answer

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Best answer

Correct answer  1. (B) 2.(B) 3. (A)

1. G1 G2… Gn

2.  A1 + A2 + A3 + … + Am-1 + Am = 1025 x 171

Therefore, m (-2 + 1027/2) =  1025 x 171 ⇒ m = 342

3.  Since n = 9, therefore

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