Answer is (B), (C), (D)
Given: f: (0, π) → R is twice differentiable function such that
Also, it is given that
This equation can be written in differential form:
-d/dx(f(x)/sinx) = 1
Thus, there exists α ∈ (0, π) for which f'(x) = 0.
As f(x) is continuous in [0, π] and differentiable in (0, π). Hence, option (C) is true
Hence, option (D) is true.