The equations of the bisectors are
3x - 4y/5 = ± 5x + 12y + 7/13
hat is, 2x − 16y − 5 = 0 and 64x + 8y + 35 = 0
Now, suppose θ be the angle between the given lines which is bisected by the bisector
2x - 16 - 5 = 0
The angle between 3x − 4y = 0 and 2x − 16y − 5 = 0 is q /2 which is certainly acute. Therefore,
Therefore, θ/2 < π/4 and So θ < π/2
Hence, 2x − 16y − 5 = 0 is the required bisector. Substituting (1, −2) in both given line, we get positive and negative values and so the required angle bisector is
64x + 8y + 35 = 0
