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in Integrals calculus by (52.5k points)

If ∫(tanx/(1 + tanx + tan2x))dx = x - k/(√Atan-1((Ktanx + 1)/√A)) + C (C is a constant of integration), then the ordered pair (K, A) is equal to 

(A) (2, 1) 

(B) (−2, 3) 

(C) (2, 3) 

(D) (−2, 1)

1 Answer

+1 vote
by (54.8k points)
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Best answer

Answer is (C) (2, 3)

Given:

Let tanx = t, that is, sec2xdx = dt.

Therefore, K = 2 and A = 3.

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