Question

Let y = y(x) be the solution of the differential equation dy/dx + 2y = f(x), where f(x) = {(1, x ∈ [0, 1]), (0, otherwise) If y(0) = 0, then y(3/2) is

(A) (e² + 1)/2e⁴

(B) 1/2e

(C) (e² - 1)/e³

(D) (e² - 1)/2e³

Answer 1

Answer is (D) (e² - 1)/2e³

Comments

bro how did you get c=e^2-/2