Answer is (D) xyy' - y2 + = 0
We know that general equation of ellipse is
x2/a2 + y2/b2 = 1
and passes through the point (0, 3). Therefore,
x2/a2 + y2/9 = 1 (1)
Differentiating the Eq. (1) with respect to x, we get
From Eqs. (1) and (2), the differential equation is