Here m = 1800 kg
Distance between the front and rear axles = 1.8 m
Distance of the centre of gravity from the front axle = 1.05 m
Let R1 and R2 be the reactions of ground on the front and rear wheels, respectively.
Now, R1 + R2 = mg = 1800 x 9.8 ...(i)
For rotational equilibrium about G
R1 x 1.05 = R2 (1.8 - 1.05)
= R2 x 0.75
or, R1/R2 = 0.75/1.05 = 5/7
or, R1 = 5/7 R2
Putting R1 = 5/7 R2 in (i) we get
5/7 R2 + R2 = 1800 x 9.8
or, R2 = {7 x 1800 x 9.8}/{12} = 10290 N
and R1 = 5/7 x 10290 = 7350 N