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+1 vote
60.1k views
in Vector algebra by (52.5k points)

If the position vectors of the vertices A, B and C of a ΔABC are, respectively, 4i + 7j + 8k, 2i + 3j + 4k and 2i + 5j + 7k, then the position vector of the point, where the bisector of ∠A meets BC is

(A) 1/2(4i + 8j + 11k)

(B) 1/3(6i + 11j + 15k)

(C) 1/3(6i + 13 + 18k)

(D) 1/4(8i + 14j + 19k)

1 Answer

+1 vote
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Best answer

Answer is (C) 1/3(6i + 13 + 18k)

From the given data, we plot the graph as shown in the following figure:

D is the point of intersection of internal angle bisector of a with BC line

Therefore, the position vector of point D is

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