Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.2k views
in Chemistry by (64.7k points)

Determine the empirical formula of an oxide of iron which has 69.9% iron and 30.1% dioxygen by mass

1 Answer

+1 vote
by (62.3k points)
selected by
 
Best answer
Element % Atomic
mass
Relative no.
of atoms
Simplest
ratio
Whole 
number ratio
Iron 69.9 56 69.9/56 = 1.25 1.25/1.25 = 1 2
dioxygen 30.0 16 30.1/16 = 1.89 1.89/1.25 1.5 3

Empirical formula = Fe2O3

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...