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0 votes
36.4k views
in Mathematical induction by (52.5k points)

The number of values of k for which the system of linear equations, 

 (k + 2)x + 10y = k 

 kx + (k + 3)y = k – 1 

has no solution, is 

(A) 1 

(B) 2 

(C) 3 

(D) infinitely many

1 Answer

+1 vote
by (54.8k points)
selected by
 
Best answer

Answer is (A) 1

Given:

(k + 2)x + 10y = k 

kx + (k + 3)y = k – 1

For no solution:

However, for k ≠ 2 for k = 2, both lines are identical and hence we have only one value of k, that is, k = 3. 

Therefore, the number of values of k is 1.

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