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in Properties of solids and liquids by (260 points)
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A tank is filled with water up to a height H. Water is allowed to come out of a hole P in one of the walls at a depth D below the surface of water express the horizontal distance x in terms of H and D.

(A) x = √[D (H – D)]

(B) x = √[{D (H – D)} / 2]

(C) x = 2√[D (H – D)]

(D) x = 4[D (H – D)]

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1 Answer

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by (30.5k points)

The correct option is (C) x = 2√[D (H – D)].

Explanation:

The pressure at the free surface of the liquid and also at outside of point P is atmospheric pressure. Hence there will be no effect of atmospheric pressure on the flow of liquid hole P. The liquid on the free surface has no kinetic energy but only potential energy. On the other hand the liquid coming out of the hole has both kinetic and potential energies. let v be the velocity of effux of the liquid coming out from the hole. According to Bemoulli's theorem.

After coming from the hole the liquid adopts a parabolic path. If it takes l sec in falling through a vertical distance (H - D), then

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