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Chlorine is prepared in the laboratory by treating manganese dioxide (MnO2) with aqueous hydrochloric acid according to the reaction

4 HCl (aq) + MnO (s) → 2H2O (l) + MnCl2 (aq) + Cl2 (g)

How many grams of HCl react with 5.0 g of manganese dioxide?

1 Answer

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4 HCl (aq) + MnO2 (s) → 2H2O (l) + MnCl2 (aq) + Cl2 (g)

4 mol                 1 mol

4(1 + 35.5) g     (54.9 + 32) g

= 146 g             = 86.9 g

Mass of HCl that reacts with 5.0 g of MnO2

= {146 g}/{86.9 g} x 5.0 g = 8.40 g HCl

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