Mass of NH3 = 34 mg = 34 x 10-3 g
Molar mass of NH3 = 17 g/mol
Amount of ammonia = {34 x 10-3 g}/{17 g/mol} = 2 x 10-3 mol
Therefore, No. of NH3 molecules in 34 mg sample
= 2 x 10-3 mol x 6.023 x 1023 mol-1
= 1.2046 x 1021
Each molecule of NH3 contains 10 protons (7 protons in N+ 3 in three H atoms).
Therefore,
(a) No. of protons in 34 mg of ammonia = 10 x 1.2046 x 1021
= 1.2046 x 1022
(b) Mass of proton = 1.675 x 10-27 kg
Therefore, total mass of protons in 34 mg of NH3
= 1.2046 x 1022 x 1.675 x 10-27 kg
= 2.015 x 10-5 kg
The number of neutrons, protons, molecules and mass does not depend upon temperature and pressure. Therefore there will be no change in the answers, if temperature and pressure are changed.