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in Limit, continuity and differentiability by (52.6k points)

Consider the function f(x) = [(x{x} + 1, 0 ≤ x < 1), (2 - {x}, 1 ≤ x ≤ 2) where {x} denotes the fractional part function. Which one of the following statements is NOT correct?

(A) lim(x 1) f(x) exists

(B) f(0) ≠ f(2)

(C) f (x) is continuous in [0, 2] 

(D) f(x) is differentiable in [0, 1) 

1 Answer

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Best answer

Answer is (C) f (x) is continuous in [0, 2]

f(1+)= f(1-) = f(1) = 2

f(0)= 1, f(2) = 2 

f(2-) = 1; f(2) = 2 

 f is not continuous at x = 2

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