Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.7k views
in Physics by (50.2k points)

The energy of the reaction Li7 + p → 2 He4 is (the binding energy per nucleon in Li7 and He4 nuclei are 5.60 and 7.06 Me V respectively.)

(A) 17.3 MeV

(B) 1.73 MeV

(C) 1.46 MeV

(D) depends on binding energy of proton

1 Answer

0 votes
by (56.7k points)
selected by
 
Best answer

Correct Answer is: (A) 17.3 MeV

Q = (2BEHe – BELi)

= (2 × 7.06 × 4 – 5.60 × 7) Mev

= 17.28 Mev.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...