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An energy of 24.6 eV is required to remove one of the electrons from a neutral helium atom.

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An energy of 24.6 eV is required to remove one of the electrons from a neutral helium atom. The energy (In eV) required to remove both the electrons from a neutral helium atom is :

(A) 38.2 

(B) 49.2

(C) 51.8 

(D) 79.0

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Correct Answer is: (D) 79.0

Energy required to remove the second e–

∴ TE = (54.4 + 24.6) = 79.0 eV.

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