Question

The length of the perpendicular from the origin, on the normal to the curve, x² + 2xy – 3y² = 0 at the point (2, 2) is

(1) 4√2

(2) 2√2

(3) 2

(4) √2

Answer 1

Answer is (2) 2√2

x² + 2xy - 3y² = 0

m_N = slope of normal drawn to curve at (2, 2) is -1

L : x + y = 4.

perpendicular distance of L from (0, 0)

Answer 2

Answer is (2) 2√2