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in Mathematics by (549 points)

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1 Answer

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AB=AB'=BB'

ΔABB' is equilateral

AB=√((a-0)2+(0-b)2)

=√(a2+b2)

AB'=√((a-0)2+(0-(-b)2)

=√(a2+6)

BB'=2b

AB=BB' =>(√(a2+b2))2 =(2b)2

=> a2+b2=4b2

=> a2=3b2

b2=a2(1-e2)

=> a2=3a2(1-e2)

=> a2=3a2(1-e2)

= 1/3=1-e2

=>e2=1-1/3=2/3

e=√2/3

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