Question

If f'(x) = tan^-1(secx + tanx), - π/2 < x < π/2, and f(0) = 0, then f(1) is equal to:

(1) (π - 1)/4

(2) (π + 2)/4

(3) (π + 1)/4

(4) 1/4

Answer 1

Answer is (3) (π + 1)/4

Answer 2

Answer is (3) (π + 1)/4