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0 votes
44.0k views
in Physics by (36.3k points)

The dimension of stopping potential V0 in photoelectric effect in units of Planck's constant 'h', speed of light 'c' and Gravitational constant 'G' and ampere A is :

(1) h2 G3/2 c1/3 A–1

(2) h–2/3 c–1/3 G4/3 A–1

(3) h1/3 G2/3 c1/3 A–1

(4) h2/3 c5/3 G1/3 A–1

2 Answers

+1 vote
by (33.0k points)
selected by
 
Best answer

v0 = hxcyGzAw

x = 0

z = –1

2 × 0 + y + 3x – 1 = 2

y = 5 

v0 = h0c5G-1A-1

+1 vote
by (51.9k points)

V = K(h)a (I)b (G)c (C)d  (V is voltage)

we know [h] = ML2T-1 

a - c = 1 ...(1)

2a + 3c + d = 2 ...(2)

-a -2c -d = -3 ...(3)

b = -1 ...(4)

on solving

c = -1

a = 0

d = 5, b = -1

V = k(h)0 (I)-1 (G)-1 (C)5

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