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0 votes
48.8k views
in Physics by (36.3k points)

The magnifying power of a telescope with tube 60 cm is 5. What is the focal length of its eye piece ?

(1) 30 cm

(2) 40 cm

(3) 20 cm

(4) 10 cm

2 Answers

+1 vote
by (33.0k points)
selected by
 
Best answer

Answer is (4) 10 cm

L = f0 + fe = 60 cm 

M = f0/fe = 5

f0 = 5fe

 6fe = 60 cm

fe = 10 cm

+1 vote
by (51.9k points)

Answer is (4) 10 cm

m = f0/fe

5 = f0/fe

f0 = 5fe

f0 + fe = 60 

6fe = 60 

fe = 10 

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