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0 votes
35.8k views
in Chemistry by (54.9k points)

The ammonia (NH3) released on quantitative reaction of 0.6 g urea (NH2CONH2) with sodium hydroxide (NaOH) can be neutralized by : 

(1) 100 ml of 0.1 N HCl 

(2) 200 ml of 0.4 N HCl 

(3) 100 ml of 0.2 N HCl 

(4) 200 ml of 0.2 N HCl

2 Answers

+2 votes
by (52.6k points)
selected by
 
Best answer

Answer is (3) 100 ml of 0.2 N HCl

Hence, NH3 will require 20 meq.

+2 votes
by (58.4k points)

Answer is (3) 100ml of 0.2NHCl

0.6 gm

10–2 mole, 10m. moles 

m. moles of NH3 = 20

m. moles of HCl = 20m moles 

Hence 1 is correct. 

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