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How much electricity in terms of Faraday is required to carry out the reduction of one mole of PbO2

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The cell reaction that takes place in a lead storage battery are:

Pb + PbO2 + 4H+ + SO4-2 → 2PbSO4 + 2H2O

In this reaction Pb shows an oxidation state of +4. It gets reduced to PbSO4 which shows an oxidation state of +2.  

In this reaction, 2 electrons are necessary for the reduction of PbO2.

Pb4+ + 2e-  -----------> Pb2+

Therefore, as 2 electrons were needed for the reduction, the Faraday’s law of electrolysis stated that:

The reduction of 1 mole of PbO2 required 2F electricity.  

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