Question

Calculate the temperature of 4.0 mol of a gas occupying 5 dm³ at 3.32 bar. (R = 0.083 bar dm³ K^-1 mol^-1)

Answer 1

Amount of the gas, n = 4.0 mol

Volume of the gas, V = 5 dm³

Pressure of the gas, p = 3.32 bar

R = 0.83 bar dm³ K^-1 mol^-1

From the gas equation,

pV = nRT

or, T = {pV}/{nR}

= {3.32 bar x 5 dm³}/{4.0 mol x 0.083 bar dm³ K^-1 mol^-1}

= 50 K