Length I = 4.234 m,
Breadth b = 1.005 m,
Thickness t = 2.01 cm = 0.0201 m
Area = 2 × (lb + bt + It)
= 2 × (4.234 × 1.005 + 1.005 × 0.0201 + 4.234 × 0.0201)
= 8.72 m2
(Rounding off to 3 significant figures)
Volume = Ibt
= 4.234 × 1.005 × 0.0201
= 8.55 × 10-2 m3