Question

The Cartesian product A x A has 9 elements along which are found (-1, 0) and (0,1). Find the set A and the remaining elements A x A.

Answer 1

Given n(A x A) = 9 = 3²

⇒n(A) = 3

But (-1, 0) and (0, 1) are in A x A

∴ A= {-1,0,1}.

Remaining elements of A x A: (-1, -1), (-1, 1),

(0,-1), (0,0), (1,-1), (1,0), (1,1).