The correct option is C) 20μF.
We first find volume of big drop Volume of big drop = 64 x volume of small drop
4/3 π.R3 =64 x 4/3 π.r3
R = 4r
Because capacitance of solid spherical body directly proportion to radius
Hence big drop capacitance = 4 x capacitance of small
Capacitance of big drop=20μF