If a body undergoes equal displacements in equal intervals of time, however small interval of time may be then velocity is said to be uniform velocity.
Particle moving along a straight line with a constant acceleration ‘a’. Let u be its velocity at time t = 0 and ‘v’ be the velocity after ‘t’ seconds. The velocity-time graph AC of this particle is shown in the figure.
Distance travelles by the particle is given by,
s = area under v-t graph
= area of the trapezium OACD
= 1/2 (OA + CD) × OD
But OA = u, CD = v and OD = t
∴ s = 1/2 (u + v) t or 2s = (u + v) t ………(1)
But, a = slope of the graph = (v - u)t
∴ t = (v - u)/a
On substituting in (1), 2s = (u + v)((v - u)/a)
i.e., v2 – u2 = 2as
or v2 = u2 + 2as.