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5.2k views
in Mathematics by (52.6k points)

Solve 30x < 200 when

(i) x is a natural number

(ii) x is an integer.

1 Answer

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Best answer

Given: 30x < 200

x < 200/30 = 6.6

(i) x is a natural number: 

Solution set = { 1, 2, 3,4, 5, 6}

(ii) x is a real number:

∴ Solution set = {… -3, -2, -1,0, 1,2, 3,4, 5, 6}

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