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From a committee of 8 persons, in how many ways can we choose a chairman and a vice chairman assuming one person cannot hold more than one position?

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Given : Number of persons in committee = 8 

To find : Two positions (chairman, vice chairman)

Since one person cannot hold more than one position, therefore chairman post can be filled in 8P1 ways and vice chairman post can be filled in 7P1 ways. 

∴ Required number of ways of choices  = 8P1 x 7P1 

= 8 x 7 = 56 

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