Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
45.1k views
in Mathematics by (54.9k points)

What is the number of ways of choosing 4 cards from a pack of 52 playing cards? In how many of these 

(i) four cards are of the same suit 

(ii) four cards belong to four different suit 

(iii) are face cards 

(iv) two red cards and two are black card 

(v) 4 cards are of the same colour.

1 Answer

+2 votes
by (52.6k points)
selected by
 
Best answer

We have, 

Number of ways of choosing 4 cards from a pack of 52 cards is the number of combinations of 52 different things taken 4 at time 

∴ Required number of ways = 52C4

= (52 x 51 x 50 x 49)/(4 x 3 x 2 x 1) = 270725

(i) There are four suits, namely diamond, club, spade, heart and each suit has 13 cards. We have to choose 4 cards of the same suit so 4 diamond cards out of 13 diamond cards can be selected in 13C4 ways. Similarly,there are 13C4 ways of choosing 4 spades and 13Cways of choosing 4 hearts. 

∴ Required number of ways 

13c13c13c13c4

= 4x13C4 = 4 x (13 x 12 x 11 x 10)/(4 x 3 x 2 x 1) = 2860

(ii) There are 13 cards in each suit we have to select 4 cards belonging to 4 different suits. There are 13C1 ways of choosing one card from 13 diamond cards, 13C1 ways of choosing 1 card from 13 cards of spades, 13C1 ways of choosing 1 card from 13 cards of club and 13C1 ways of choosing 1 card from 13 cards of hearts. By multiplication principle, the required number of ways 

13C13C1 x 3C3C1 

= 13 x 13 x 13 x 13 = 134  =28561

(iii) Face cards means Kings, Queen, Jack there are 4 suits, each suit has 3 face cards. Therefore there are 12 face cards and 4 are to be selected out of 12 cards, in 12C4 ways Required number of ways = 12C4

= (12 x 11 x 10 x 9)/(4 x 3 x 2 x 1) = 495

(iv) There are 26 red cards and 26 black cards. 

∴ We have select 2 red and 2 black cards. This can be done in 26C2 x 26C2 ways. 

= (26 x 25)/(2 x 1) x (26 x 25)/(2 x 1)

= 325 x 325 = 105625

∴ Required number of ways = 26C2 x 26C2

= (26 x 25)/(2 x 1) x (26 x 25)/(2 x 1)

= 325 x 325 = 105625

(v) There are 26 red and 26 black cards

∴ 4 red cards can be selected in 26C4 ways 4 black cards can be selected in 26C4 ways 

∴ Required number of ways = 26C4 + 26C4

= 2x26C4 = (26 x 25 x 24 x 26)/(4 x 3 x 2 x 1) = 29900

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...