We are required to find the number of permutations which begin with the letter A.
There are 11 letters in the given word of which A – 2, 1-2,N-2,
When A is fixed in the first place, remaining 10!/2!2! letters can be arranged in ways.
∴ Required permulations
= (10 x 9 x 8 x 7 x 6 x 5 x 4 x 3)/(2 x 1) = 907200