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If S1, S2, S3 are the sum of first ‘n’ natural numbers, their squares and their cubes, respectively, show that 9S2 = S3(1 + 8S1)

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If S1, S2, S3 are the sum of first ‘n’ natural numbers, their squares and their cubes, respectively, show that 9S2  = S3(1 + 8S1)

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Multiply by and + by 9

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