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Without using distance formula, show that points (-2, -1), (4, 0) (3, 3) and (-3, 2) are the vertices of a parallelogram.

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Without using distance formula, show that points (-2, -1), (4, 0) (3, 3) and (-3, 2) are the vertices of a parallelogram. 

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Given points are A(-2, -1) B(4, 0), C(3, 3) and D(-3, 2) 

Clearly 

Slope of AB = Slope of CD and Slope of BC = Slope of DA 

∴ opposite sides of the quadrilateral ABCD are parallel 

⇒ ABCD is a parallelogram

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