(i) Atomic weight of Helium = 4, i.e. 4 u is mass of 1 atom, 52 u is mass of 1/4 × 52 = 13 atoms.
(ii) 4 g of He contains 6.022 × 1023 He atoms / 52 g of He contains ?
(6.022 x 1023 x 52)/4 = 7.8286 × 1023 atoms.
(iii) 1 mole of He contains 6.022 × 1023 atoms, 52 moles of He contains 52 × 6.022 × 1023 = 3.131 × 1023 atoms.