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How many atoms are present in 4 ml of NH3 at STP?

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22400 ml of NH3 contains = 4 × 6.022 × 1023 atoms [∵ NH3 contains 4 atoms]. 1ml of NH3 contains = (4 x 6.022 x 1023)/22400 = 1.07 × 1020 atoms.

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