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in Chemistry by (49.6k points)

An organometallic compound on analysis was found to contain, C = 64.4%, H = 5.5% and Fe = 29.9%. Determine its empirical formula. (At. mass of Fe = 56 u).

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Element % Atomic weight Relative no. of atoms Divide by least Simplest ratio
C 64.4 12 64.4/12 = 5.36 5.36/0.53 = 10.1 10
H 5.50 1 5.50/1 = 5.50 5.50/0.53 = 10.4 10
Fe 29.9 56 29.9/56 = 0.53 0.53/0.53 = 1 1

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