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1 M solution of NaNO3 has density 1.25 g cm-3. Calculate its molality. (Mol. weight of NaNO3 = 85 g mol-1).

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Mass of solution = Volume of solution × density of solution 

Mass of solution = 1000 cm3 × 1.25 g cm-3 = 1250 g 

Mass of solute = 85 g; Mass of solvent = 1250 – 85 = 1165 g.

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