Question

200 cm³ of a solution of a dibasic acid contains 1.512 g of the acid and the normality of the solution is 0.12. Calculate 

(i) the equivalent mass and 

(ii) the molecular mass of the acid.

Answer 1

(i) Mass of the acid in one dm³ of the solution = 1.512 × 5 = 7.56 g.

(ii) Molecular mass of the acid = eq. mass × basicity = 63 × 2 = 126.