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in Mathematics by (52.6k points)

If the origin is the centroid of the triangle PQR with vertices P (2a, 4, 6) Q(-4, 3b, -10) and R(8, 14, 2c) then find the values of a, b, c.

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((2a - 4 + 8)/3, (4 + 3b + 14)/3, (6 - 10 + 2c)/3) = (0, 0, 0)

⇒ (2a + 4)/3 = 0 ⇒  a = - 2

similarly b = - 6 and c = 2.

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