Let P(n) : 12 + 22 + 32 + ………… + n2 = (n(n + 1)(2n + 1))/6
Step 1: P(1) is true
when n = 1; L.H.S = 12 = 1
R.H.S = (1(1 + 1)(2 + 1))/6
∴ L.H.S = R.H.S
∴ P(1) is true
step 2: Assume that P(m) is true
= R.H.S
∴ P(m+1) is true
Conclusion: P(1) is true
⇒ P(m) is true
⇒ P(m+1) is true
∴ By principle of mathematical induction, the result is true for all natural numbers ‘n’.