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Prove that  12 + 22 + 32 + ………… + n2 = (n(n + 1)(2n + 1))/6

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Let P(n) : 12 + 22 + 32 + ………… + n2 = (n(n + 1)(2n + 1))/6

Step 1: P(1) is true

when n = 1; L.H.S = 12 = 1

R.H.S = (1(1 + 1)(2 + 1))/6

∴ L.H.S = R.H.S 

∴ P(1) is true

step 2: Assume that P(m) is true

= R.H.S 

∴ P(m+1) is true 

Conclusion: P(1) is true 

⇒ P(m) is true 

⇒ P(m+1) is true 

∴ By principle of mathematical induction, the result is true for all natural numbers ‘n’.

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