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Write the atomic number at an element with outer configuration, (i) 4s^1, (ii) 3d^3.

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Write the atomic number at an element with outer configuration, (i) 4s1, (ii) 3d3.

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(i) Electronic configuration for outer configuration 4s1 = 1s2, 2s2, 2p6, 3s2, 3p6, 4s1. 

Atomic number = 19 

(ii) Exact configuration for outer configuration 3d3. 

1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d3 = 23 

Atomic number = 23

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