Let set of students taking coffee = C & set of students taking tea = T
Also set of students who take either Tea or Coffee = C ∪ T
n (T) = 150 n(C) = 225
n(C ∩ T) = 100 ; n(C ∪ T) = ?
n(C ∪ T) = n(C) + n(T) – n (C ∩ T)
= 150 + 225 – 100 = 275
Number of students taking neither Tea nor Coffee
= n(∪), n (C ∪ T) = 600 – 275 = 325