Question

Some elements are wrongly placed in the decreasing order of the property mentioned. Rectifying the fault, place them in correct order of the property. Also, furnish reason for the correction done 

(a) F > O > N > C (second ionization potential 

(b) N > Si > C > P (electronegativity of the elements) 

(c) Na > Mg > Al > Si (First ionization potential).

Answer 1

(a) O > F > N > C, second ionization potential of oxygen is highest since electron is to be removed from half filled configuration for rest follow the order of size.

(b) N > C > P > Si, nitrogen has smallest size and so has higher tendency to attract shared pair of electrons. 

(c) Si > Al > Mg > Na, silicon has highest first ionization potential due to smallest size, Mg is exception i.e., has higher ionization potential than aluminium because of ns² configuration which is stable.