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in Chemistry by (49.7k points)

Calculate the kinetic energy of one mole of nitrogen at 400 K.

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(KE)mol = 3/4 RT= 3/2 × 8.314 x JK-1mol-1 × 400K = 498.9 J mol-1

Note: From problems 16 and 19, it can be observed that the kinetic energy of one mole of any two gases, at the same temperature, will be the same.

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