Given: x = 2 + √3
\(\frac{1}{a} = \frac{1}{2+\sqrt3}\)
\(= \frac{1}{2+\sqrt3}\) x \(\frac{2-\sqrt3}{2-\sqrt3}\)
\(= \frac{(2-\sqrt3)}{((2)^2 - (\sqrt3)^2)}\)
\(= \frac{(2-\sqrt3)}{(4-3)}\)
\(= (2-\sqrt3)\)
Now,
\(x + \frac{1}{x}\) = (2 + √3) + (2 – √3)
= 2 + √3 + 2 – √3
= 4