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in Chemistry by (62.3k points)

At a certain temperature and total pressure of 105 Pa, iodine vapour contains 40% by volume of I atoms.

I2(g) ⇌ 2I(g)

Calculate KP for the equilibrium.

1 Answer

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Total pressure of equilibrium mixture = 105 Pa

Partial pressure of iodine atoms (I) = \(\frac{40}{100}\) x (105 Pa) = 0.4 x 105 Pa

Partial pressure of iodine molecules (I2)

\(\frac{60}{100}\) x (105 Pa) = 0.6 x 105 Pa

I2(g) (0.6 x 105 Pa) ⇌ 2I(g) (0.4 x 105 Pa)

KP\(\frac{p^2I}{pI_2}\) = \(\frac{(0.4 \times 10^5\, Pa)^2}{(0.6 \times 10^5\, Pa)}\) = 2.67 x 104 Pa

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