Question

A sample of HI(g) is placed in flask at a pressure of 0.2 atm. At equilibrium the partial pressure of HI(g) is 0.04 atm. What is K_p for the given equilibrium?

2HI ⇌ H₂(g) + I₂(g).

Answer 1

pHI = 0.04 atm

pH₂ = 0.08 atm

pI₂ = 0.08 atm

K_p = \(\frac{pH_2 \times pI_2}{p^2HI}\)

= \(\frac{(0.08\, atm)\times (0.08\, atm)}{(0.04\,atm)\times (0.04\,atm)}\) = 4