(x + 2) (x2 + 25) – 10x (x + 2)
Take (x + 2 ) as common factor;
= (x + 2)(x2 + 25 – 10x)
= (x + 2) (x2 – 10x + 25)
Expanding the middle term of (x2 – 10x + 25 )
= (x + 2) (x2 – 5x – 5x + 25)
= (x + 2){x(x – 5) – 5( x – 5)}
= (x + 2)(x – 5)(x – 5)
= (x + 2)(x – 5)2
Therefore, (x + 2) (x2 + 25) – 10x(x + 2) = (x + 2)(x – 5)2.